2^x^2-4+10=32^8-x

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Solution for 2^x^2-4+10=32^8-x equation: 



2^x^2-4+10=32^8-x

We move all terms to the left:

2^x^2-4+10-(32^8-x)=0

We add all the numbers together, and all the variables

2^x^2-(32^8-x)+6=0

We get rid of parentheses

2^x^2+x+6-32^8=0

We add all the numbers together, and all the variables

x+2^x^2-1099511627770=0

We move all terms containing x to the left, all other terms to the right

x+2^x^2=1099511627770

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